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x^2-146x+48^2=0
We add all the numbers together, and all the variables
x^2-146x+2304=0
a = 1; b = -146; c = +2304;
Δ = b2-4ac
Δ = -1462-4·1·2304
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-146)-110}{2*1}=\frac{36}{2} =18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-146)+110}{2*1}=\frac{256}{2} =128 $
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